Research output: Contribution to journal › Journal article

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**Direct measurement of the energy dissipated by quantum turbulence.** / Bradley, Ian; Fisher, Shaun; Guénault, A.M.; Haley, Richard; Pickett, George; Potts, David; Tsepelin, Viktor.

Research output: Contribution to journal › Journal article

Bradley, I, Fisher, S, Guénault, AM, Haley, R, Pickett, G, Potts, D & Tsepelin, V 2011, 'Direct measurement of the energy dissipated by quantum turbulence', *Nature physics*, vol. 7, no. 6, pp. 473-476. https://doi.org/10.1038/NPHYS1963

Bradley, I., Fisher, S., Guénault, A. M., Haley, R., Pickett, G., Potts, D., & Tsepelin, V. (2011). Direct measurement of the energy dissipated by quantum turbulence. *Nature physics*, *7*(6), 473-476. https://doi.org/10.1038/NPHYS1963

Bradley I, Fisher S, Guénault AM, Haley R, Pickett G, Potts D et al. Direct measurement of the energy dissipated by quantum turbulence. Nature physics. 2011 Jun;7(6):473-476. https://doi.org/10.1038/NPHYS1963

@article{cebc4a4013374a3cac5e4292828bcab6,

title = "Direct measurement of the energy dissipated by quantum turbulence",

abstract = "The lack of a general solution to the governing Navier-Stokes equations means that there is no fundamental theory of turbulence. In the simpler case of pure quantum turbulence, the tangle of identical singly quantized vortices in superfluids at T similar to O may provide a deeper understanding of turbulence in general. The well-known Kolmogorov theory(1) predicts the energy distribution of turbulence and how it decays. In normal systems the turbulent energy is generally only a small perturbation on the total thermal energy of the supporting medium. In quantum turbulence, however, the energy is accessible. A stationary condensate is necessarily in its ground state with zero enthalpy. Thus quantum turbulence accounts for the entire free energy of the superfluid and there are no other contributions. Here, we exploit this property to make the first direct measurement of the energy released by freely decaying quantum turbulence. Our results are consistent with a Kolmogorov energy spectrum with an inferred Kolmogorov constant remarkably similar to those of classical fluids. ",

keywords = "SUPERFLUID HE-3-B, GRID TURBULENCE, FINITE CHANNEL, VELOCITY, MODEL ",

author = "Ian Bradley and Shaun Fisher and A.M. Gu{\'e}nault and Richard Haley and George Pickett and David Potts and Viktor Tsepelin",

year = "2011",

month = jun

doi = "10.1038/NPHYS1963",

language = "English",

volume = "7",

pages = "473--476",

journal = "Nature physics",

issn = "1745-2473",

publisher = "Nature Publishing Group",

number = "6",

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T1 - Direct measurement of the energy dissipated by quantum turbulence

AU - Bradley, Ian

AU - Fisher, Shaun

AU - Guénault, A.M.

AU - Haley, Richard

AU - Pickett, George

AU - Potts, David

AU - Tsepelin, Viktor

PY - 2011/6

Y1 - 2011/6

N2 - The lack of a general solution to the governing Navier-Stokes equations means that there is no fundamental theory of turbulence. In the simpler case of pure quantum turbulence, the tangle of identical singly quantized vortices in superfluids at T similar to O may provide a deeper understanding of turbulence in general. The well-known Kolmogorov theory(1) predicts the energy distribution of turbulence and how it decays. In normal systems the turbulent energy is generally only a small perturbation on the total thermal energy of the supporting medium. In quantum turbulence, however, the energy is accessible. A stationary condensate is necessarily in its ground state with zero enthalpy. Thus quantum turbulence accounts for the entire free energy of the superfluid and there are no other contributions. Here, we exploit this property to make the first direct measurement of the energy released by freely decaying quantum turbulence. Our results are consistent with a Kolmogorov energy spectrum with an inferred Kolmogorov constant remarkably similar to those of classical fluids.

AB - The lack of a general solution to the governing Navier-Stokes equations means that there is no fundamental theory of turbulence. In the simpler case of pure quantum turbulence, the tangle of identical singly quantized vortices in superfluids at T similar to O may provide a deeper understanding of turbulence in general. The well-known Kolmogorov theory(1) predicts the energy distribution of turbulence and how it decays. In normal systems the turbulent energy is generally only a small perturbation on the total thermal energy of the supporting medium. In quantum turbulence, however, the energy is accessible. A stationary condensate is necessarily in its ground state with zero enthalpy. Thus quantum turbulence accounts for the entire free energy of the superfluid and there are no other contributions. Here, we exploit this property to make the first direct measurement of the energy released by freely decaying quantum turbulence. Our results are consistent with a Kolmogorov energy spectrum with an inferred Kolmogorov constant remarkably similar to those of classical fluids.

KW - SUPERFLUID HE-3-B

KW - GRID TURBULENCE

KW - FINITE CHANNEL

KW - VELOCITY

KW - MODEL

UR - http://www.scopus.com/inward/record.url?scp=79957980200&partnerID=8YFLogxK

U2 - 10.1038/NPHYS1963

DO - 10.1038/NPHYS1963

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JO - Nature physics

JF - Nature physics

SN - 1745-2473

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